[" The height of mercury column in a barometer in a "],[" Calcutta laboratory was recorded to be "75cm." Calculate "],[" this pressure in SI and CGS units using the following "],[" data : Specific gravity of mercury "=13*6," Density of "],[" water "=10^(3)kg/m^(3),g=9*8m/s^(2)" at Calcutta.Pressure "],[=h rho g" in usual symbols."]

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of water = 10^3 kg/m^3, g=9.8 m/s^2 at Calcutta. Pressure =h rho g in usual symbols.

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of water = 10^3 kg/m^3, g=9.8 m/s^2 at Calcutta. Pressure =h rho g in usual symbols.

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of water = 10^3 kg/m^3, g=9.8 m/s^2 at Calcutta. Pressure =h rho g in usual symbols.

The height of mercury column in a barometer in the Kolkata laboratory was recorded to be 75 cm. Calculate the pressure at Kolkata in SI unit using the following data: Density of mercury = 13.6xx10^(3)kgm^(-3) , pressure = rhogh , where h is the height of mercury column, rho is the density of mercury, and g is the acceleration due to gravity)

Density of mercury is 13.6 g cm^(-3) . Its density in kg m^(-3) is

Calculate the total pressure at the bottom of a lake of depth 5.1 m (atm pressure =10^(5) P), density of water =10^(3)kg//m^(3),g=10m//s^(2)

A mercury barometer in a physics laboratory shows a 732 mm vertical column of mercury. Calculate the atmospheric pressure in pascal. [Given density of mercury , rho = 1.36 xx 10^(4) kg m^(-3) , g = 9.8 m s^(-2) ]

At a given place is barometer records a pressure of 70 cm of mercury. If the mercury in the barometer is replaced by water, what would be the height of the water column? Take density of mercury =13600kg//m^(3) density of water =1000kg//m^(3)

Calculate the pressure at the bottom of a fresh water lake of depth 10 m. The atmospheric pressure = 76 cm of mercury and the density of mercury = 13.6g*cm^(-3) .