Home
Class 14
MATHS
[" The point on the curve "y=sqrt(x-1)" ...

[" The point on the curve "y=sqrt(x-1)" where the tangent is perpendicular to the line "],[2x+y-5=0" is "],[[" A) "(2,-1)," B) "(10,3)," (C) "(2,1)," D) "(5,-2)]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The points on the curve y=sqrt(x-3) , where the tangent is perpendicular to the line 6x+3y-5=0 are

Find the points on the curve y=sqrt(x-3) , where the tangent is perpendicular to the line 6x+3y-5=0 .

Find the point on the curve y=sqrt (x-3) , where the tangent is perpendicular to the line 6x+3y-5 = 0

The point on the curve y=3x^(2)+2x+5 at which the tangent is perpendicular to the line x+2y+3=0

Find the points on the curve 4x^2+9y^2=1 , where the tangents are perpendicular to the line 2y+x=0

Find the points on the curve 4x^2+9y^2=1 ,where the tangents are perpendicular to the line 2y+x=0

Find the points on the curve 4x^2+9y^2=1 , where the tangents are perpendicular to the line 2y+x=0

Find the points on the curve 4x^2+9y^2=1 , where the tangents are perpendicular to the line 2y+x=0 .

The point on the curve y=x^2+5 , the tangent at which is perpendicular to the line x+2y=2 is