ydx-(x+2y^(2))dy=0

Consider the differential equation ydx-(x+y^(2))dy=0 . If for y=1, x takes value 1, then value of x when y = 4, is

Solve the equation ydx+(x-y^(2))dy=0

ydx+(x-y^(2))dy=0

Solve: ydx+(x-y^(3))dy=0

Solve the equation ydx+(x-y^2)dy=0

Solve the equation ydx+(x-y^2)dy=0

Solve the equation ydx+(x-y^2)dy=0

Solve the equation ydx+(x-y^2)dy=0