[" The equitialent resistance and potential difference" "],[" between A and B for the circuit are respectively."],[[" 2.4."," 25.9"],[" (1) "4Omega,8V," (2) "8Omega,4V],[" (3) "2Omega,2V," (4) "16Omega,8V]]

[" 3,In the shown circuit,when the voltage between "],[qquad [" A and "B" is "16" V the voltage between "C" and "D" is "],[8" V.When the voltage between "C" and "D" is "15" V,"],[" what is the voltage (in "V" ) between "A" and "B" ? "]],[[" A "0," 2 Omega "," 8 Omega "],[" B "," ? "," R "],[" 2 Omega "," (2) "5," o "D],[" (1) "7.5," (4) "4," 8 Omega "]],[" (3) "3," (4) "],[" (3) "3," ."],[" ."]

In the shown circuit the following battery is of emf 4V and internal resistance 8 Omega . Find the potential difference between points x and y as shown in the circuit.

Calculate the current through each resistance in the given circuit. Also calculate the potential difference between the points a and b. E_1 = 6V, E_2 = 8V, E_3 =10V , R_1 =5 Omega , R_2 =10 Omega, R_3 =4Omega Assume that all the cless have no internal resistance.

Calculate the current through each resistance in the given circuit. Also calculate the potential difference between the points a and b. E_1 = 6V, E_2 = 8V, E_3 =10V , R_1 =5 Omega , R_2 =10 Omega, R_3 =4Omega Assume that all the cless have no internal resistance.

In the part of the circuit shown in the figure, the potential difference between points V_(A)-V_(B)=16V . The current passing through the 2Omega resistance will be

In the part of the circuit shown in the figure, the potential difference between points V_(A)-V_(B)=16V . The current passing through the 2Omega resistance will be