A body of masss 1kg is allowed to fall freely under gravity. Find the mimimum and kinetic energy of the body 5 second after it starts falling. Take g=`10 ms^(-2)`

Potential energy of a body is the energy possessed by the body by virtue of its position. P.E. =mgh where the symbols have their usual meaning. Kinetic energy of a body is the energy possessed by the body by virtual of its velocity. K.E.=(1)/(2)m upsilon^(2) Energy can neither be created nor be destroyed. However energy can be changed from one form to other, such that energy appearing in one form is equal to the energy disappearing in the other form. With the help of the passage given above, choose the most appropriate alternative for each of the following question : A body of mass 1 kg is allowed to fall freely under gravity. The momentum of the body 5 second after it starts falling is

A body having masss oif 100g is allowed to fall freely under the action of gravity. Calcualate the kinetic energy after 10s. Take g= 9.8ms^(-2) .

The kinetic energy of freely falling body

A body having a mass 100 gm is allowed to fall freely under gravity. Calculate KE after 10 seconds g=9.8 m//s^(-2) .

A body of mass 10 kg is kept at a height of 5 m. It is allowed to fall and reach the ground. What is the kinetic energy possessed by the body just before hitting the ground? (Take g = 10m//s^(2) ).

A body, freely falling under gravity will have uniform