[" Let "f:[-(pi)/(3),(pi)/(6)]rarr" B defined by "f(x)=2cos^(2)x+sqrt(3)sin2x+1." Find "B" such that "f^(-1)" exists.Also find "],[f^(-1)(x)" ."]

let f:[-pi/3,pi/6]rarr B defined by f(x)=2cos^2x+sqrt3sin2x+1 . Find B such that f^-1 exists. Also find f^-1

Let f:[-(pi)/(3),(2pi)/(3)]rarr[0,4] be a function defined as f(x) as f(x) = sqrt(3)sin x -cos +2 . Then f^(-1)(x) is given by

Let f:[-(pi)/(3),(2pi)/(3)]rarr[0,4] be a function defined as f(x) = sqrt(3)sin x -cosx +2 . Then f^(-1)(x) is given by

Let f : [-(pi)/(2), (pi)/(2)] rarr [3, 11] defined as f(x) = sin^(2)x + 4 sin x + 6 . Show that f is bijective function.

Let f : [-(pi)/(2), (pi)/(2)] rarr [3, 11] defined as f(x) = sin^(2)x + 4 sin x + 6 . Show that f is bijective function.

If f:(-(pi)/(2),(pi)/(2))rarr(-oo,oo) is defined by f(x)=tan x then f^(-1)(2+sqrt(3))=

If f:[(pi)/(2),(3 pi)/(2)]rarr[-1,1] and is defined by f(x)=sin x,thenf^(-1)(x) is given by

Let f:[-(pi)/(3),(2 pi)/(3)]rarr[0,4] be a function defined as f(x)=sqrt(3)sin x-cos x+2. Then f^(-1)(x) is given by sin^(-1)((x-2)/(2))-(pi)/(6)sin^(-1)((x-2)/(2))+(pi)/(6)(2 pi)/(3)+cos^(-1)((x-2)/(2))(d) none of these

Let f: { - pi/3, (2pi)/(3)} rarr [0, 4] be a function defined as f(x)=sqrt(3) sin x - cos x + 2 . Then f^(-1)(x) is given by

Function f[(1)/(2)pi, (3)/(2)pi] rarr [-1, 1], f(x) = cos x is