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ABCD is a parallelogram and O is a poin...

ABCD is a parallelogram and O is a point in its interior. Prove that
(i) `ar(triangleAOB)+ar(triangleCOD)`
`=(1)/(2)ar("||gm ABCD").`
(ii) `ar(triangleAOB)+ar(triangleCOD)=ar(triangleAOD)+ar(triangleBOC)`.

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