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|[1,5,7],[6,7,2],[1,2,3]|...

|[1,5,7],[6,7,2],[1,2,3]|

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State true of false. [[2,3,4],[5,6,7],[1,2,3]]=[[4,2,3],[7,5,6],[3,1,2]]

Show that [[5,-1],[6,7]] [[2,1],[3,4]] ne [[2,1],[3,4]] [[5,-1],[6,7]]

Show that: [[5,-1],[6,7]][[2,1],[3,4]] ne [[2,1],[3,4]][[5,-1],[6,7]]

Expand |{:(3,-5,4),(7,6,1),(1,2,3):}|

Show that A=[(1,5,6),(5,2,7),(6,7,3)] is a symmetric matrix as A^T =A .

If {[(5,1,4),(7,6,2),(1,3,5)][(1,6,-7),(6,2,4),(-7,4,3)][(5,7,1),(1,6,3),(4,2,5)]}^(2020)=[(a_(1),a_(2),a_(3)),(b_(1),b_(2),b_(3)),(c_(1),c_(2),c_(3))] , then the value of 2|a_(2)-b_(1)|+3|a_(3)-c_(1)|+4|b_(3)-c_(2)| is equal to

If {[(5,1,4),(7,6,2),(1,3,5)][(1,6,-7),(6,2,4),(-7,4,3)][(5,7,1),(1,6,3),(4,2,5)]}^(2020)=[(a_(1),a_(2),a_(3)),(b_(1),b_(2),b_(3)),(c_(1),c_(2),c_(3))] , then the value of 2|a_(2)-b_(1)|+3|a_(3)-c_(1)|+4|b_(3)-c_(2)| is equal to

I: If A=[(0,1,2),(2,3,4),(4,5,-6)],B=[(-1,2,3),(0,1,0),(0,0,-1)] then 4A-5B=[(5,-6,-7),(8,7,16),(16,20,-19)] II:If A=[(1,2,3),(3,2,1)]B=[(3,2,1),(1,2,3)] then 3B-2A=[(7,2,-3),(-3,2,7)]