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Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.

Text Solution

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Here, base of the triangle `= 12cm`
Let hypothenuse is `x`.
Then, perpendicular will be , `18-x`.
Now, from Pythagoras theorem,
`12^2+(18-x)^2 = x^2`
`=> 144+324+x^2-36x = x^2`
`=>36x = 468 -> x = 13`
So, hypotenuse is `13` cm and perpendicular will be `18-13 = 5` cm.
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