`3x^3+2x^2+3x+2=?`

Number of integers in the range of the function f(x) = (x^3 + 2x^2 + 3x + 2) / (x^3+2x^2+2x+1) : x in R-{0} is :

x^(3) + 3x^(2) + 3x + 2 = (x+2) (………)

lim_ (x rarr oo) ((2x-3) ^ (2) (3x + 2) ^ (3)) / ((2x + 1) ^ (5))

Find the sum of the following algebraic expressions : 3x^(3) - 5x^(2) + 2x + 1 , 3x - 2x^(3) - x^(3) , 2x^(2) - 7x + 9

int(3x^(3)+2x^(2)+3x+1)/(3(x^(2)+1))dx

int (3x^3+2x^2+3x+1)/(3(x^2+1)) dx=

divide 3x^3+2x^2+x-1 by 3x-2

Simplify: (3x^(3)-2x^(2)-3x-3)-(x^(3)-2x^(2)+3x-4)

The equation 5x^(5)+3x^(4)-2x^(3)-2x^(2)+3x+5=0 is a reciprocal equation of

Find the interval where f(x)={(-4/3x^3+2x^2+3x,,xgt0),(2xe^x,,xle0):} increasing