[" Let "A=[[2,b,1],[b,b^(2)+1,b],[1,b,2]]," where "b>0." Then "],[" mininum value of "(det(A))/(b)" is ".]

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A = [{:(2, b,1),(b, b^(2)+1,b),(1, b,2):}], " where "b gt 0 . Then, the maximum value of ("det"(A))/(b) is

Let the matrix A and B be defined as A=[[3 , 2], [ 2 , 1]] and B=[[3, 1],[ 7, 3]] then the absolute value of det. (2 A^9 B^-1) is

Let Delta=|(a,a^(2),0),(1,2a+b,(a+b)^(2)),(0,1,2a+3b)| then

If A=[[1,2],[-1,-2]],B=[[2,a],[-1,b]] and (A+B)^2=A^2-B^2 .Find values of a and b.

Let f(x)=(1+b^2)x^2+2b x+1 and let m(b) the minimum value of f(x)dot As b varies, the range of m(b) is (a) [0,1] (b) (0,1/2] (c) [1/2,1] (d) (0,1]