[" 128.Let "A=[[cos alpha,-sin alpha],[sin x,cos c]],(alpha in R)" such that "],[A^(32)=[[0,-1],[1,0]]" .Then a value of "alpha" is "]

Let A=([cos alpha,-sin alphasin alpha,cos alpha]),(alpha in R) such that A^(32)=([0,-11,0]). Then a value of alpha is:

Let A = [{:("cos"alpha, -"sin"alpha), ("sin"alpha, "cos"alpha"):}], (alpha in R) such that A^(32) = [{:(0, -1), (1, 0):}] . Then, a value of alpha is

Let A = [{:(cos alpha,- sin alpha ), ( sin alpha , cos alpha ):}], (a in R) such that A ^(32) = [{:(0,-1), (1, 0):}] is the value of alpha is (pi)/(2^(k)), then the value of k is

Let A_(alpha)=[[cos alpha,-sin alpha,osin alpha,cos alpha,00,0,1]]

If A=[(cos alpha, -sin alpha, 0),(sin alpha, cos alpha,0),(0,0,1)] then A^(-1) is

If A=[(cos alpha, - sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)] then (AdjA)^(T)=

cos alpha,-sin alpha,1sin alpha,cos alpha,1cos(alpha+beta),-sin(alpha+beta),1]|

cos alpha,-sin alpha,1sin alpha,cos alpha,1cos(alpha+beta),-sin(alpha+beta),1]|

Delta=det[[0,sin alpha,-cos alpha-sin alpha,0,sin betacos alpha,-sin beta,0]]

Find inverse of the matrix A=[[cos alpha, -sin alpha, 0 ],[ sin alpha, cos alpha, 0],[ 0, 0, 1]]