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If the area of a parallelogram ABCD is 3...

If the area of a parallelogram ABCD is `30 cm^2`,then the length of altitude AQ is

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Area of parallelogram ` A= 30cm^2`
We can divide this parallelogram into two triangles of equal area by drawing diagonal `AC`.
Please refer to video for the diagram.
`:.` Area of `Delta ACD`+Area of `Delta ABC` `= 30`
`=> 2**`Area of `Delta ABC= 30`
`=>`Area of `Delta ABC= 15`
`=>1/2**BC**AQ = 15`
`=>6**AQ = 30`
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