If `sintheta +cos theta =m` and `sec theta + cosec theta =n` then `n(m+1)(m-1)` equals

If sin theta + cos theta = m and sec theta + " cosec " theta = n then

If sin theta + cos thea = m and sec theta+ cosec theta = n , then n (m + 1) (m - 1) =

If sin theta+cos theta=m and sec theta+cos ec theta=n then n(m+1)(m-1) equals

If sin theta + cos theta = m and sec theta + "cosec" theta = n, prove that n(m^(2)-1) = 2m.

If m= sin theta+ cos theta and n= sec theta+cosec theta , prove that n (m + 1) (m-1) = 2m .

If cos theta + sin theta = m , sec theta + cosec theta =n , What is m//n ?

If cos ec theta - sin theta = m and sec theta - cos theta = n, then show that (m ^(2) n ) ^(2//3) + (mn ^(2)) ^( 2//3) = 1.

If "cosec" theta - sin theta = m and sec theta - cos theta = n, then find a relation between m and n, independent of theta .