if `cos^2theta/a=sin^2theta/b` then `cos^4theta/a+sin^4theta/b=?`

If cos^2 theta-sin^2 theta= 1/2 then cos^4 theta-sin^4 theta=?

sin^2theta+cos^4theta=cos^2theta+sin^4theta

If (cos^(2)theta)/(a)=(sin^(2)theta)/(b) then (cos^(4)theta)/(a)+(sin^(4)theta)/(b)=0

If (cos^(2) theta)/(a) = (sin^(2) theta)/(b) then (cos^(4) theta)/(a) + (sin^(4) theta)/(b) =

Prove the following sin^4theta-cos^4theta=sin^2theta-cos^2theta=1-2cos^2theta=2sin^2theta-1

If sin theta + sin^(2) theta =1 then cos^(4) theta + cos^(8) theta + 2 cos^(6) theta =

If cos theta =4/5 then sin^2 theta cos theta + cos^2 theta sin theta is equal to :

If sin theta+sin^2theta=1 , show that cos^4theta+cos^2theta=1 .

1-8 cos ^(2) theta + 8 cos ^(4) theta= A) sin 4 theta B) cos 4 theta C) sin ^(4) theta + cos ^(4) theta D) sin ^(4) theta - cos ^(4) theta

The value of cos^4theta+sin^4theta-6cos^2theta is (a) cos2theta (b) sin2theta (c) cos4theta (d) none of these