[" (Take "g=" rom "],[" 20.A rigid insulated wire frame in the form of a right "],[" triangle "ABC" ,is set in a vertical plane as shown "],[" two beads of equal masses "m" each and carrying in "],[" and "q_(2)" are connected by a cord of length "l" and "],[" without friction on the wires."],[" Considering the case when the beads are station "],[" determine "]

A rigid insulated wire frame in the form of a right-angled triangle ABC is set in a vertical plane as shown in fig. two beads of equal masses m each and carrying charges q_(1) and q_(2) are connected by a cord of length l and can slide without friction on the wires. Cinsidering the case when the beads are stationary, determine (i) the angel alpha (ii) the tension in the cord, and (iii) The normal recation on teh beads. If the cord is now cut, what are the value of the charges for which the beads continue to remain stationary?

A rigeid insulated wire frame in the form of a right-angled traingle ABC is set in a vertical plane as shown in fig. two beads of equal masses m each and carrying charges q_(1) and q_(2) are connected by a cord of length l and can slide without friction on the wires. Cinsidering the case when the beads are stationary, determine (i) the angel alpha (ii) the tension in the cord, and (iii) The normal recation on teh beads. If the cord is now cut, what are the value of the charges for which the beads continue to remain stationary?

Two beads A & B of equal mass m are connected by a light inextensible to move on a connected to move on a frictionless ring in vertical plane. The beads are released from rest as shown. The tension in the cord just after the release is:

An equailaral triangle ABC formed from a uniform wire has two small identical beads initially located at A. The triangle is set rotating about the vertical axis AO. Then the beads are released from rest simultaneously and allowed to slide down, one along AB and the other along AC as shown. Neglectig frictional effects, the equatities that are conserved as the beads slids down, are

A equilaterial triangle ABC formed from a uniform wire has two small identical beads initially located at A . The triangle is set rotating about the vertical axis AO . Then the beads are released from rest simultaneously and allowed to slide down. one long. AB and the other along AC as shown. Neglecting frictional effects, the quantities that are conserved as the beads slide down, are. .

A equilaterial triangle ABC formed from a uniform wire has two small identical beads initially located at A . The triangle is set rotating about the vertical axis AO . Then the beads are released from rest simultaneously and allowed to slide down. one long. AB and the other along AC as shown. Neglecting frictional effects, the quantities that are conserved as the beads slide down, are. .

A bead of mass m is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equastion is x^(2) =4ay . The wire frame is fixed and the bead is released from the point y=4a on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by y=a is

A bead of mass m is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equastion is x^(2) =4ay . The wire frame is fixed and the bead is released from the point y=4a on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by y=a is

A bead of mass m is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equastion is x^(2) =4ay . The wire frame is fixed and the bead is released from the point y=4a on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by y=a is

A smooth wire of length 2pir is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed about the vertical diameter AB, as shown in the figure, the bead is at rest with respect to the circular ring at potion P as shown. Then the value of omega^(2) is equal to: