If `asintheta+bcostheta=c` then `(a-btantheta)/(b+atantheta)=`

If asintheta+bcostheta=c then prove that acostheta-bsintheta=sqrt(a^2+b^2-c^2)

If asintheta+bcostheta=c , then acostheta-b sintheta is equal to

If asintheta+bcostheta=c , find acostheta-bsintheta=?

If acostheta-bsintheta=c , then prove that: asintheta+bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

If acostheta-bsintheta=c , then prove that: asintheta+bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

If acostheta+bsintheta=c , then prove that: asintheta-bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

If x=(acostheta+bcostheta)/(a+b), then

If acostheta-bsintheta=c , then asintheta+bcostheta= (a) +-sqrt(a^2+b^2+c^2) (b) +-sqrt(a^2+b^2-c^2) (c) +-sqrt(c^2-a^2-b^2) (d) None of these

If atantheta =b ,then acos 2theta+b sin2 theta=

If ((asintheta-bcostheta)/(asintheta+bcostheta))=((a^2-b^2)/(a^2+b^2))^k and tan theta=a/b then k=