Let `f:(0,1)->R` be defined by `f(x)=(b-x)/(1-bx)`, where b is constant such that `0 lt b lt 1` .then ,

Let f:(0,1)->R be defined by f(x)=(b-x)/(1-bx) , where b is constant such that 0 ltb lt 1 .then ,

Let f:(0,1)->R be defined by f(x)=(b-x)/(1-bx) , where b is constant such that 0 ltb lt 1 .then ,

Let f: (0,1) to R be defined by f(x)=(b-x)/(1-bx) where b is a constant such that 0 lt b lt 1 Then:

Let, f:(0,1) rarr R be defined by f(x)=(b-x)/(1-b x) where b is a constant such that 0 lt b lt 1 . Then,

Let f:(0,1)->R be defined by f(x)=(b-x)/(1-bx) , where b is constant such that 0 ltb lt 1 .then ,(a)f is not invertible on (0,1) (b) f ≠ f − 1 on (0,1) and f ' ( b ) = 1/ f ' ( 0 ) (c) f = f − 1 on (0,1) and f ' ( b ) = 1/ f ' ( 0 ) (d) f − 1 is differentiable on (0,1)

Let the function f: R-{-b}->R-{1} be defined by f(x)=(x+a)/(x+b) , a!=b , then f is

Let the function f;R-{-b}rarr R-{1} be defined by f(x)=(x+a)/(x+b),a!=b, then