The mode of the following frequency distribution is 46 and the total frequency is 150. Find the missing frequencies x and y.

Explanation

Here, we are given total frequency is `150`.

`6+8+17+x+42+30+y+8 = 150`

`=> x+y+111 = 150`

`=>x+y = 39`

It means, both `x` and `y` does not exceed `42`.

So, our modal class wil be `40-50`.

Now, Mode can be given by formula,

`Mode = l+(f_1-f_0)/(2f_1-f_0-f_2)**h`

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