Prove that `2sqrt3` is an irrational number

Explanation

Rational numbers can be written in the form `p/q` where `p` and `q` are intergers and `q !=0`.

Now, given number is ,

`2sqrt3 = 2sqrt3**sqrt3/sqrt3 = 6/sqrt3`

So, it is in `p/q` form and `q !=0`.

But, as `q` is not an integer,

given number is not a rational number.

Hence, `2sqrt3` is an irrational number.