[" The height "y" and the distance "x" along the "],[" horizontal plane of a projectile on a certain planet "],[" (with on surrounding atmosphere) are given by "y],[=(8t-5t^(2))" meter and "x=6t" meter,where tis in "],[" second.The velocity with which the projectile is "],[" projected is: "]

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t-5t^(2)) meter and x = 6t meter , where t is in second. The velocity with which the projectile is projected is

The height y and the distance x along the horizontal plane of a prohectile on a certain planet (with no surrounding atmosphere) are given by y=8t- 5t^(2) meter and x=6t meter,where t is in seconds.The velocity with which the projectile is projected is (Acceleration due to gravity =9.8 m s^(-2) )

The height y nad the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t^2) m and x = 6t m , where t is in seconds. The velocity with which the projectile is projected at t = 0 is.

The height y nad the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t^2) m and x = 6t m , where t is in seconds. The velocity with which the projectile is projected at t = 0 is.

The height y and the distance x along the horizontal plane of a projectile on a certain planet [with no surrounding atmosphere] are given by y=[5t-8t^2] metre and x = 12t metre where t is the time in second. The velocity with which the projectile is projected is:

The height y and the distance x along the horizontal plane of a projectile on a certain planet [with no surrounding atmosphere] are given by y=[5t-8t^2] metre and x = 12t metre where t is the time in second. The velocity with which the projectile is projected is:

The height y and the distance x along the horizontal plane of projectile on a certain planet (with no atmosphere on it) are given by y = (8t-5t^(2)) metre and x = 6t metre , where time t is in seconds. Find the initial velocity with which the projectile is projected.

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t - 5t^(2))m . The velocity with which the projectile is projected is