Home
Class 12
MATHS
[" 4Suppose refractive index is given as...

[" 4Suppose refractive index is given as "mu=A+(8)/(lambda)" ,were "A" and "B" are constants and "lambda" is wavelength then the "],[" then the dimesion of are same as that of "],[[" (1) Wavelength "," (2) Pressure "," (3) Area "," (4) Volume "]]

Promotional Banner

Similar Questions

Explore conceptually related problems

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

The refractive index of a medium is given by mu=A+(B)/(lambda^(2)) where A and B are constants and lambda is the wavelength of light. Then the dimensions of B are the same as that of

The refractive index ( mu ) of glass is related to the wavelength (lambda) of incident light as mu = A +(B)/(lambda^(2)) , where A and B are constants. Find out the dimensions of A and B.

How does refractive index (mu) of a material vary with respect to wavelenght (lambda) . (A and B are constants).

How does refractive (µ) of a material vary with respect to wavelength ( lambda )? A and B are constants