41. The emf of a Daniell cell at 298 K is E Za ZnSO, Cuso, Cu (0.01 M (1.0 M) When the concentration of ZnSO, is 1.0M and that of Cuso, is 0.01 M, the emf changed to Ex What is the relationship between E, and E2 (a) Ei>E (b) E

The emf of a Daniell cell at 298 K is E_(1) Zn|ZnSO_(4)(0.01 M)||CuSO_(4)(1.0M)|Cu When the concentration of ZNSO_(4) is 1.0 M and that of CuSO_(4) is 0.01 M , the emf changed to E_(2) . What is the relationship between E_(1) and E(2) ?

The emf of a Daniell cell at 298 K is E_(1) Zn|ZnSO_(4)(0.01 M)||CuSO_(4)(1.0M)|Cu When the concentration of ZNSO_(4) is 1.0 M and that of CuSO_(4) is 0.01 M , the emf changed to E_(2) . What is the relationship between E_(1) and E(2) ?

The e.m.f of the following Daniell cell at 298K is E_1 . Zn|ZnSO_4(0.01M)||CuSO_4(1.0)|Cu When concentration of ZnSO_4 is 1.0 M and that of CuSO_4 is 0.01M, if e.m.f changed to E_2 . What is the relationship between E_1 and E_2 ?

The e.m.f of the following Deniell at 298 K is E_1 , Zn//ZnSO_4 (0.01 M)// // CuSO_4 (1.0 M)//Cu When the concentration of ZnSO_4 is 1.0 M and that of CuSO_4 is 0.01M, the e.m.f. changed to E_2 . What is the relationship between E_1 and E_2 ?

The emf of a Daniell cell at 298 K is E_1 Zn underset((0.01M))|NnSO_4 |underset((1.0M))| CuSO_4 | Cu when the concentration of ZnSO_4 is 1.0 M and that of CuSO_4 is 0.01 M the emf changed to E_2 what is the relationship between E_1 and E_2 .

The emf of a Daniel cell at 298 K is E_1 The cell is Zn|ZnSO_(4)(0.01M)||CuSO_(4)(1M)|Cu When the concentration of ZnSO_4 is changed to 1M and that of CuSO_4 , to 0.01 M, the emf changes to E_2 The relationship between E_1 and E_2 will be

The EMF of a Daniel cell at 298K is E_(1) . The cell is: Zn(s)abs( ZnSO_(4) (0.01M)) | abs(CuSO_(4)(1.0M)) Cu(s). When the concentration of ZnSO_(4) is 1.0 M and that of CuSO_(4) is 0.01 M the emf changes to E_(2) . What is the relationship between E_(1) and E_(2) ?