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[" Example "16.1" Find the quantity of h...

[" Example "16.1" Find the quantity of heat required to convert "],[40g" of ice at "-20^(@)C" into water at "20^(@)C" .Given "],[L_(" ice ")=0.336times10^(6)J/kg" .Specific heat of "ice=2100J/kg-K" ."],[" Specific heat of water "=4200J/kg-K]

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Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

Find the amount of heat required to convert 10 kg ice at -10^(@)C to water at 50^(@)C . Given specific heat of ice 2100Jkg^(-1)K^(-1) , specific heat of water 4200Jkg^(-1)K^(-1) and latent heat of ice 3.36xx10^5Jkg^(-1)

The amount of heat energy required to convert 1 kg of ice at -10^@ C to water at 100^@ C is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice = 2100 J kg^(-1) K^(-1) , specific heat capacity of water = 4200 J kg^(-1) K^(-1) .

Calcuate the heat required to convert 0.6 kg of ice at - 20^(@)C , kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given the specific heat capacity of ice =2100 j kg^(-1) K^(-1) , specific heat capacity of water =4186 j kg^(-1) K^(-1) latent heat ice =3.35xx10^(5) j kg^(-1) and latent heat of steam =2.256xx10^(6)j kg^(-1)

Calculate the heat required to convert 3 kg of ice at -12^(@)C kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given, specific heat capacity of ice = 2100 J kg^(-1) K^(-1) specific heat capicity of water = 4186 J kg^(-1)K^(-1) Latent heat of fusion of ice = 3.35 xx 10^(5) J kg^(-1) and latent heat of steam = 2.256 xx 10^(6) J kg^(-1) .