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[" Example "16.135" gof water at "30^(@)...

[" Example "16.135" gof water at "30^(@)C" and "5g" of ice at "-20^(@)C" are "],[" mixed together in a calorimeter.Find the final temperature of "],[" mixture.Water equivalent of calorimeter is negligible,specific "],[" heat of ice = 0.5cal "g^(-1)c^(-1)" and latent heat of ice = 80cal "g^(-1)" ."]

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About 5g of water at 30^(@)C and 5g of ice at -20^(@)C are mixed together in a calorimeter. Calculate final temperature of the mixture. Water equivalent of the calorimeter is negligible. Specific heat of ice =0.5"cal"g^(-1)C^(@)-1) and latent heat of ice =80"cal"g^(-1)

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5g of water at 30^@C and 5 g of ice at -29^@C are mixed together in a calorimeter. Find the final temperature of mixture. Water equivalent of calorimeter is negligible, specific heat of ice = 0.5 cal//g-^@C and latent heat of ice =80 cal//g .

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5 g of water at 30^(@) C and 5 g of ice at -20^(@) C are mixed together in a caloritmeter. The water equivalent of calorimeter is negliglible and specific heat and latent heat of ice are 0.5 cal/ g^(@) C and 80 cal/g repsectively. The final temperature of the mixture is

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19 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice =0.5calg^(-1) (.^(@)C)^(-1) and latent heat of fusion of ice =80calg^(-1)