The time period of a body executing SHM is 0.05 s. if the amplitude is 4 cm, then what will be the maximum velocity and maximum acceleration of the body?

The time period of a body executing S.H.M. is 0.05 s and the amplitude of vibration is 4 cm. What is the maximum velocity of the body ?

The time period of an oscillating body executing SHM is 0.05 sec and its amplitude is 40 cm. The maximum velocity of particle is :

Time period of a particle executing SHM is T = 1 second and its amplitude of vibration is A = 0.04 m. Determine the maximum velocity and maximum acceleration of the particle.

The particle executes simple harmonic motion have periodic time 0.05s and amplitude 4 cm, then what its maximum velocity?

A particle of mass 0.5g is executing SHM with a time period of 2s and an amplitude of 5 cm. Calculate its (i) maximum velocity, (ii) maximum acceleration and (iii) velocity, acceleration and force acting on the particle when it is at a distance of 4 cm from its position of equilibrium.

A body executing SHM with amplitude of 2 cm makes (30/pi) vibrations in 1 min. What is the maximum velocity of the body during the motion?

The velocity-time graph of a particle executing SHM is as shown in the figure. The amplitude and maximum acceleration of the particle respectively are

A body is executing S.H.M. with an amplitude of 2cm makes 30/pi vibrations per minute. What maximum velocity of the body during the motion ?

A body executing SHM has a maximum velocity of 1ms^(-1) and a maximum acceleration of 4ms^(-1) . Its time period of oscillation is

If amplitude of particle executing SHM is doubled, which of the following quantities are doubled a) Time period b) Maximum velocity c) Maximum acceleration d) Total energy