In the adjoining figure, BD = CE and `angleADB=angleAEC=90^(@)`, prove that
(i) `DeltaABD cong DeltaACE` (ii) ABC is an isosceles triangle.

In the adjoining figure, angleBAC=angleBDC and angleABC=angleBCD . Prove that : (i) DeltaABC cong DeltaDCB (ii) DeltaABE cong DeltaDCF .

In the adjoining figure, angleBAC=angleBDC and angleABC=angleBCD . Prove that : (i) DeltaABC cong DeltaDCB (ii) DeltaABE cong DeltaDCF .

In the adjoining figure, AD = DC and bisects angleADC . Prove that DeltaADB cong DeltaCDB .

In the adjoining figure, BD = DC and AE = ED. Prove that area of DeltaACE = (1)/(4) " area of " DeltaABC

In the adjoining figure, BD = DC and AE = ED. Prove that area of Delta ACE = (1)/(4) " area of " Delta ABC

In the given figure PQ is a tangent to the circle at A. AB and AD are bisectors of angleCAQandanglePAC . If angleBAQ=30^(@) , prove that : (i) BD is a diameter of the circle. (ii) ABC is an isosceles triangle

In the adjoining figure, prove that DeltaABD~=DeltaACD ,

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure) . Show that (i) DeltaABD ~= DeltaACE (ii) AB = AC i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure) . Show that (i) DeltaABD ~= DeltaACE (ii) AB = AC i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure) . Show that (i) DeltaABD ~= DeltaACE (ii) AB = AC i.e., ABC is an isosceles triangle.