If `f` is a real valued function given by `f(x)=27 x^3+1/(x^3)a n dalpha,beta` are roots of `3x+1/x=2.` Then, `f(alpha)=f(beta)=-9` (b) `f(alpha)=10` (c) `f(beta)=-10` (d) none of these

If f(x) = 27x^3 + 1/x^3 and alpha, beta are the roots of 3x + 1/x = 2 then

If f (x) = 27x^(3) -(1)/(x^(3)) and alpha, beta are roots of 3x - (1)/(x) = 2 then

If f (x) = 27x^(3) -(1)/(x^(3)) and alpha, beta are roots of 3x - (1)/(x) = 2 then

If f(x)=64x^3+1/x^3 and alpha,beta are the roots of 4x+1/x=3 . Then,value of f(x)=

If f(x)=64x^(3)+(1)/(x^(3)) and alpha,beta are the roots of 4x+(1)/(x)=3. Then

If f(x)=27x^(3)+(1)/(x^(3)) and alpha,beta are the roots of the equation 3x+(1)/(x)=2, then -f(alpha) is equal to

If alpha,beta are the zeroes of polynomial f(x)=x^2-p(x+1)-c ,then (alpha+1)(beta+1) =

Let f(x)=ax^3+bx^2+cx+1 has exterma at x=alpha,beta such that alpha beta < 0 and f(alpha) f(beta) < 0 f . Then the equation f(x)=0 has three equal real roots one negative root if f(alpha) (a) 0 and f(beta) (b) one positive root if f(alpha) (c) 0 and f(beta) (d) none of these