Home
Class 11
MATHS
[" (a) "55m/sec" " (b) "110m/sec" (c) "5...

[" (a) "55m/sec" " (b) "110m/sec" (c) "550m/sec" (d) "660m/sec],[" Anobject moving with speed of "25m/sec" is deaccelerated at arate given by "(dV)/(dt)=-2.5sqrt(V)],[" where "v=instantan" evs speed the time taken byojecttocometorest would be: "],[[" (a) "8sec," (b) "1sec," (c) "2sec," (d) "4sec]]

Promotional Banner

Similar Questions

Explore conceptually related problems

An object moving with a speed of 6.25m/s , is decreased at a rate given by (dv/dt)=-2.5sqrt(v) where v is instantaneous speed, The time taken by the object to come to rest, would be

An object moving with a speed of 6.25 m/s , is decelerated at a rate given by: (dv)/(dt)= -2.5sqrt(v) where v is the instantaneous speed The time taken by the object to come to rest would be:

An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dv/dt=-2.5sqrt v where v is the instantaneous speed. The time taken by the object, to come to rest, would be

An object moving with a speed of 6.25 m//s , is deceleration at a rate given by : (dv)/(dt) = -25 sqrt(v) , where v is instantaneous speed. The time taken by the obeject, to come to rest, would be :

An object , moving with a speed of 6.25 m//s , is decelerated at a rate given by : (dv)/(dt) = - 2.5 sqrt (v) where v is the instantaneous speed . The time taken by the object , to come to rest , would be :

An object , moving with a speed of 6.25 m//s , is decelerated at a rate given by : (dv)/(dt) = - 2.5 sqrt (v) where v is the instantaneous speed . The time taken by the object , to come to rest , would be :

An object moving with a speed of 6.25 "m.s"^(-1) is decelerated at a rate given by: (dv)/(dt) = -2.5 sqrt(v) where v is the instantaneous speed. What would be the time taken by the object to come to rest?