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Knowing the electron gain enthalpy value...

Knowing the electron gain enthalpy values for ` O to O^(-) and O to O^(2-) ` as `-141 and 702 kJ mol^(–1)` respectively, how can you account for the formation of a large number of oxides having `O^(2-)` species and not `O^(–)`?
(Hint: Consider lattice energy factor in the formation of compounds).

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Knowing the electron gain enthalpy values for O to O^(-) and OtoO^(2-) as -141 and 702 kJcdotmol^(-1) respectively, how can you account for the formation of a large number of oxides having O^(2-) species and not O^(-) ? (Hint: Consider lattice energy factor in the formation of compounds).

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The electron gain enthalpy (in kJ/mole) of F, O, N and C respectively are :