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KC SINHA-अवकल समीकरण -अभ्यास 23.4
- अवकल समीकरण sec^(2)x tan y dx+ sec^(2) y tan x dy= 0 का हल है
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- ydx + xdy = xy(dy -dx)
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- (1-x^(2))dy + xy dx = xy^(2)dx
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- tan y dx+ sec^(2)y tan x dy=0
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- " cosec " x logy (dy)/(dx) +x^(2)y=0
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- (x^(2)-yx^(2))dy + (y^(2) +x^(2)y^(2)) dx=0
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- (dy)/(dx) = (1+x^(2))(1+y^(2))
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- 2 sin 3y dx + 3x cos 3ydy=0
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- (dy)/(d) = x/(x^(2)+1)
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- (e^(x) + e^(-x)) (dy)/(dx) = (e^(x)-e^(-x))
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- (x+2) (dy)/(dx) =x^(2) + 4x-9
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- (dy)/(dx) = sin^(3)x cos^(2)x + xe^(x)
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- (dy)/(dx) = (1- cosx)/(1+ cosx)
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- y log y dx - x dy=0
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- (dy)/(dx) + y=1, y ne 1
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- (x+1) (dy)/(dx) =2xy
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- x^(5) (dy)/(dx)= -y^(5)
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- e^(x) sqrt(1-y^(2)) dx + y/x dy =0
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- x(1+y^(2)) dx - y(1-x^(2)) dy =0 निम्नलिखित अवकल समीकरणों को हल करें...
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- (dy)/(dx) = 1+x +y + xy
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