` (( 1 + i ) ^ 3 ) /( 4 + 3i) ` को A + iB के रूप में लिखिए |

Explanation

` (( 1 + i ) ^ 3 ) /( 4 + 3i) = ( 1 ^ 3 + 3. 1 ^ 2 . i + 3. 1 . i ^ 2 + i ^ 3 ) /( 4 + 3i ) = ( 1 + 3 i - 3 - i ) /( 4 + 3i ) `
` = ( - 2 + 2i) /( 4 + 3 i) = (( - 2 + 2i ) ( 4 - 3i))/((4 + 3 i ) ( 4- 3i ) ) `
` = ( - 8 + 8i + 6i - 6i ^ 2 ) / ( 4 ^ 2 - 9i ^ 2 ) = ( - 2 + 14 i ) /( 25 ) = - ( 2)/( 25 ) + i ( 14 ) /(25 ) `.