` sqrt ( - 2 ) sqrt ( - 3 ) = sqrt(( - 2 ) (-3)) = sqrt 6 `
(i) True
(ii) False

Explanation

Explanation : ` sqrt ( - 2 ) sqrt ( - 3 ) = sqrt ( 2 xx ( -1 ) ) sqrt ( 3 xx ( - 1)) `
` = sqrt 2 sqrt ( -1 ) .sqrt3 sqrt ( - 1 ) = sqrt 2 i xx sqrt 3 i = sqrt 6 i^ 2 = - sqrt6 `
Note : ` sqrt a sqrt b = sqrt ( ab )` तभी जब a और b में से कम - से कम एक अऋणात्मक हो
` therefore sqrt ( -2 ) sqrt ( - 3 ) ne sqrt (( - 2 ) (-3)) `