[" In a triangle "ABC," if "A" is "(1,2)" and equations of the medians "],[" through "B" and "C" are "x+y=5" and "x=4" respectively,then "B],[" must be the point "]

In a triangle ABC, if A is (1, 2) and the equations of the medians through B and c are x+ y= 5 and x= 4 respectively then B must be:

in a triangle ABC, if A is (1,2) and the equations of the medians through B and c are x+y=5 and x=4 respectively then B must be:

In a triangle ABC, coordinates of A are (1,2) and the equations of the medians through B and C are x+y=5 and x=4 respectively. Find the coordinates of B and C.

In a triangle ABC, co-ordinates of A are (1,2) and the equations to the medians through B and C are x+y=5 and x=4 respectively.Then the co-ordinates of B and C will be

The vertex A of triangle ABC is at origin.The equation of median through B and C are 15x-4y=240 and 15x-52y+240=0 respectively.Then

In a triangle ABC, coordinate of A are (1,2) and the equations of the medians through B and C are respectively, x+y=5&x=4 . Then area of DeltaABC (in sq. units) is:

In a triangle ABC, if A-=(1,2) and the internal angle bisectors through B and C are y=x and y=-2x, then the inradius r of DeltaABC is