[" Let "S={1,2,3,......,9}." For "k=1,2,......,5," let "N_(k)" be the number of subsets of "S," each "],[" containing five elements out of which exactly "k" are odd.Then "N_(1)+N_(2)+N_(3)+N_(4)+N_(4)+N_(5)=?]

Let S={1,2,3......,9}. For k=1,2,.....5, let N_(k) be the number of subsets of S,each containing five elements out of which exactly k are odd.Then N_(1)+N_(2)+N_(3)+N_(4)+N_(5)=?210(b)252(c)125 (d) 126

Let S={1,2,3ddot,9}dotFork=1,2, 5,l e tN_k be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N_1+N_2+N_3+N_4+N_5=? 210 (b) 252 (c) 125 (d) 126

Let A={1,2,3,4,...,n} be a set containing n elements,then for any given k<=n, the number of subsets of A having k as largest element must be

Let A = {1,2,3,4,...,n} be a set containing n elements, then for any given k leqn , the number of subsets of A having k as largest element must be

Let N be the number of integer solutions of the equation n_(1) + n_(2) + n_(3) + n_(4)= 17 when n ge 1, n_(2) ge -1, n_(3) ge 3, n_(4) ge 0 . If N= ""^(17)C_(K) , then find K.

For positive integers k=1,2,3,....n, let S_(k) denotes the area of /_AOB_(k) such that /_AOB_(k)=(k pi)/(2n),OA=1 and OB_(k)=k The value of the lim_(n rarr oo)(1)/(n^(2))sum_(k-1)^(n)S_(k) is

Let S_(n) denote the sum of first n terms of an AP and S_(2n) = 3S_(n) . If S_(3n) = k S_(n) , then the value of k is equal to

Observe the following statements : (A) : 10 is the mean of a set of 7 obervations and 5 is the mean of a set of 3 observations. The mean of a combined set is 9. (R ) : If bar(x)_(i)(i = 1,2,…,k) are the means of k - series n_(i)(I = 1,2,3,…,k) respectively, then the combined or composite mean is bar(x) = (n_(1)bar(x)_(1) + n_(2) bar(x)_(2) + ...+ n_(k)bar(x_(k)))/(n_(1)+n_(2)+...+n_(k))

Observe the following statements : (A) : 10 is the mean of a set of 7 obervations and 5 is the mean of a set of 3 observations. The mean of a combined set is 9. (R ) : If bar(x)_(i)(i = 1,2,…,k) are the means of k - series n_(i)(I = 1,2,3,…,k) respectively, then the combined or composite mean is bar(x) = (n_(1)bar(x)_(1) + n_(2) bar(x)_(2) + ...+ n_(k)bar(x_(k)))/(n_(1)+n_(2)+...+n_(k))