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If 0 lt thetaltpi/2 ,tantheta=(cos2 9^(...

If `0 lt thetaltpi/2 ,tantheta=(cos2 9^(@)+sin2 9^(@))/(cos2 9^(@)-sin2 9^(@))` then `theta=`

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(cos9^(@) + sin 9^(@))/(cos9^(@) - sin9^(@))=

(cos9^(@)+sin9^(@))/(cos9^(@)-sin9^(@))=?

(cos 9^(@) + sin 9^(@))/(cos 9^(@) - sin 9^(@)) equals

(cos 9^(@) +sin 9^(@))/(cos 9^(@) -sin 9^(@)) is equal to :

(cos9^(@)+sin9^(@))/(cos9^(@)-sin9^(@))=tan54^(@)

(cos 9^@ + sin 9^@ )/( cos 9^@ - sin 9^@ ) =

The value of (cos 9^(@) +sin 9^(@))/(cos 9^(@) -sin 9^(@)) is equal to-

(cos 9^(circ)+sin 9^(0))/(cos 9^(circ)-sin 9^(circ))=

sin9^(@)+cos9^(@)=sqrt(2)sin54^(@)

(cos9^@+sin9^@)/(cos9^@-sin9^@)=