A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm from the mean position is `8 cm/s^(2)` The maximum speed of the particle is

A particle executing simple harmonic motion has an amplitude of 6 cm. Its acceslleration at a distance from the mean position 2 cm is 8 cm s^-1 . The maximum speed of the particle is,

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is 8 cm/s^2 , then the maximum speed of the particle will be

A particle executing SHM has amplitude of 4cm, and its acceleration at a distance of 1cm from the mean position is 3cm^(-2) . What will its velocity be when it is at a distance of 2 cm from its mean position?

A particle executing a simple harmonic motion has a period of 6 sec.The time taken by the particle to move from the mean position to half the amplitude is