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If f1(x)=||x|-2| and f2(x)=|f(n-1)(x) ...

If `f_1(x)=||x|-2| and f_2(x)=|f_(n-1)(x) -2|` for all `n geq 2, n in N`, then number of solution of the equation `f_2015(x)=2` is

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