Evaluate : `int("x"^2+1)/(("x"+1)^2)"dx"`

Explanation

To evaluate the integral \(\int \frac{x^2 + 1}{(x + 1)^2} \, dx\), we can follow these steps:

### Step 1: Rewrite the integrand
We start by rewriting the integrand:
\[ \frac{x^2 + 1}{(x + 1)^2} = \frac{x^2 + 2x + 1 - 2x}{(x + 1)^2} = \frac{(x + 1)^2 - 2x}{(x + 1)^2} \]
This simplifies to:
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