If the depth d to which a bullet of kinetic energy K can penetrate into a human body of modulus of electicity E, using the method of dimension, establish a relation between d, K and E . If `K=cd^(x) E^(y)`, fill x+y in OMR sheet. Modulus of elasticity =Force/Area ,`xx l/(Deltal)`

The depth x to which a bullet penetrates a human body depends on (i) coeffeicint of elasticity, eta and (ii) KE (E_k) of the bullet, By the method of dimensions, show that x prop ((E_k)/(eta))^(1//3)

The velocity of sound waves 'v' through a medium may be assumed to depend on : (i) the density of the medium 'd' and (ii) the modulus of elasticity 'E' . Deduce by the method of dimensions the formula for the velocity of sound . Take dimensional constant K=1.

The velocity v of sound waves, through a medium may be assumed to depend on density of the medium, d and Modulus of elasticity (E) . Modulus of elasticity is a ratio of stress to strain and stress is force per unit area. Deduce by the method of dimensions the formula for the velocity of sound.

The SI unit of energy is J = kg m^2 s^(-2), that of speed upsilon is ms^(-1) and of acceleration a is ms^(-2) which of the formulae for kinetic energy (K) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body). (a) K = m^2 upsilon^3 (b) K = (1)/(2)m upsilon^2 (c ) K= ma (d) K =(3)/(16)m upsilon^2 (e ) K = (1)/(2) m upsilon^2 +ma

The SI unit of energy is J = kg m^2 s^(-2), that of speed upsilon is ms^(-1) and of acceleration a is ms^(-2) which of the formulae for kinetic energy (K) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body). (a) K = m^2 upsilon^3 (b) K = (1)/(2)m upsilon^2 (c ) K= ma (d) K =(3)/(16)m upsilon^2 (e ) K = (1)/(2) m upsilon^2 +ma

For a body executing S.H.M. : (a) Potential energy is always equal to its K.E. (b) Average potential and kinetic energy over any given time inteval are always equal. (c ) Sum of the kinetic and potential energy at any point of time is constant. (d) Average K.E in one time period is equal to average potential energy in one time period . Choose the most approprate ooption from the options given below :

The time period of oscillation of a body is given by T=2pisqrt((mgA)/(K)) K: Represents the kinetic energy, m mass, g acceleration due to gravity and A is unknown If [A]=M^(x)L^(y)T^(z) , then what is the value of x+y+z?

The time period of oscillation of a body is given by T=2pisqrt((mgA)/(K)) K: Represents the kinetic energy, m mass, g acceleration due to gravity and A is unknown If [A]=M^(x)L^(y)T^(z) , then what is the value of x+y+z?

Arrhenius studies the effect of temperature on the rate of a reaction and postulated that rate constant varies with temperature exponentially as k=Ae^(-E_(a)//RT) . This method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. If x is the fraction of molecules having energy greater than E_(a) it will be given by : a) x=-(E_(a))/(RT) b) In x=-(E_(a))/(RT) c) x=e^(E_(a)//RT) d) Any of these