`(sintheta+sin2theta)/(1+costheta+cos2theta)`

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

For -pi/2 lt theta lt pi/2, (sintheta + sin 2theta)/(1+costheta + cos2theta) lies in the interval

For -pi/2 lt theta lt pi/2, (sintheta + sin 2theta)/(1+costheta + cos2theta) lies in the interval

(sintheta-2sin^3theta)/(2cos^3theta-costheta) = …………….

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .

(sin5theta+sin2theta-sintheta)/(cos5theta+2cos3theta+2cos^2theta+costheta) is equal to

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1

If A = [(sintheta ,- costheta), (costheta, sintheta)] and B = [(costheta , sin theta),(-sintheta, cos theta)] . Compute (sin theta) A + (cos theta) B.