An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. Find the probability of getting (a) 2 red balls (b) 2 blue balls (c) one red and one blue ball.

Explanation

Here, probability of drawing one red ball ` = 7/11`

Probability of drawing one blue ball ` = 4/11`

(a) Probability of drawing two red balls with replacement` = 7/11**7/11 = 49/121`




(b) Probability of drawing two blue balls with replacement` = 4/11**4/11 = 16/121`



(c)Here, we can have two cases.

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