A soap bubble of radius r and surface tension T is given a potential V. Show that the new radius R of the bubble is related with the initial radius by the equation
`P(R^(3) -r^(3)) +4T (R^(2)-r^(2)) = (in_(0)V^(2)R)/(2)` where P is the atmospheric pressure.

A soap bubble of radius 'r' and surface tension 'T' is given a potential of 'V' volt. If the new radiys 'R' of the bubble is related to its initial radius by equation. P_(0)[R^(3) - r^(3)] + [lambda T [R^(2) - r^(2)] - epsilon_(0) V^(2)R//2 = 0 , where P_(0) is the atmospheric pressure. Then find lambda

The excess pressure inside a soap bubble P and the radius R of the bubble are related as

The excess pressure inside a soap bubble P and the radius R of the bubble are related as

Two soap bubbles of radius R_1 and R_2 combine isothermally to form a new soap bubble. Find radius of new soap bubble

Two soap bubble of radius 2r and 3r are in contact with each other. If the radius of curvature of the interface between the bubble in nr then find the value of n :

Excess pressure inside a soap bubble of radius r and surface tension T is

A soap bubble of radius r is placed on another bubble of radius 2r . The radius of the surface common to both the bubbles is