The container shown in figure has two chambers separated by a partition of volumes `V_(1) =2.0 L` and `V_(2) =3.0 L`. The chambers contain `mu_(1) 4.0` and `mu_(2)=5.0` mole of a gas at pressure `p_(1) =1.00` atm and `P_(2) =2.00` atm. Calculate the pressure after the partition is removed and the mixture attains equilibrium.

The container shown in Fig. 9(EP).6 has two chambers, separated by a partition, of volumes V_(1) = 2.0 litre and V_(2) = 3.0 litre . The chambers contains mu_(1) = 4.0 and mu_(2) = 5.0 "moles" of a gas at pressures p_(1) = 1.00 atm and p_(2) = 2.00 atm . calculate the pressure after the partition is removed and the mixture attains equilibrium.

A container is divided into two chambers by a partition. The volume of first chamber is 4.5 litre and second chamber is 5.5 litre. The first chamber contain 3.0 moles of gas at pressure 2.0 atm and second chamber contain 4.0 moles of gas at pressure 3.0 atm. After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is "x"xx10^(-1) atm. Value of x is "___" .

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V_1 and contains ideal gas at pressure P_1 and temperature T_1 .The other chamber has volume V_2 and contains ideal gas at pressure P_2 and temperature T_2 . If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V_1 and contains ideal gas at pressure P_1 and temperature T_1 .The other chamber has volume V_2 and contains ideal gas at pressure P_2 and temperature T_2 . If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V_1 and contains ideal gas at pressure P_1 and temperature T_1 .The other chamber has volume V_2 and contains ideal gas at pressure P_2 and temperature T_2 . If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be