`(A),(B),`and `(C)` are`:`

If a,b,c are in G.P., then (A) (a-b)/(b-c)=a/a (B) (a-b)/(b-c)=a/b (C) (a-b)/(b-c)=a/c (D) (a-b)/(b-c)=b/a

The expression (a-b)^3+\ (b-c)^3+\ (c-a)^3 can be factorized as (a) (a-b)(b-c)(c-a) (b) 3(a-b)(b-c)(c-a) (c) -3\ (a-b)(b-c)(c-a) (d) (a+b+c)(a^2+b^2+c^2-a b-b c-c a)

Prove: |(a+b,b+c,c+a),( b+c,c+a, a+b),( c+a, a+b,b+c)|=2|(a, b, c),( b, c, a),( c, a, b)|

If a+b+c= 0, then the value of ((a+b)/c + (b+c)/a + (c+a)/b) ((a)/(b+c) + b/(c+a) + c/(a+b)) is :

|{:(a-b, b-c, c-a),(b-c, c-a, a-b),(c-a, a-b, b-c):}|=

If a+b+c= 0 , then ((a+b)/(c ) + (b+c)/(a) + (c+ a)/(b)) ((c )/(a+b) + (b)/(a+c) + (a)/(b+c)) = ?

Prove: |(a, b-c,c-b),( a-c, b, c-a),( a-b,b-a, c)|=(a+b-c)(b+c-a)(c+a-b)