यदि `cot theta =(15)/(8)` हो, तो `((2+ 2 sin theta )(1-sin theta ))/((1+ cos theta)(2-2 cos theta))` का मान ज्ञात करो।

Explanation

दिया है: `cot theta =(15)/(8)`
`therefore ((2+2sin theta )(1-sin theta ))/((1+cos theta )(2-2 cos theta))`
`=(2(1+sin theta )(1-sin theta))/(2(1+cos theta)(1-cos theta))`
`implies(2(1-sin ^(2)theta))/(2(1-cos ^(2)theta))=(cos^(2)theta )/(sin ^(2)theta)=((cos theta)/(sin theta ))^(2) =(cot theta )^(2) =((15)/(8))^(2)=(225)/(64)`