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[" 3.The molar conductivity of "0.025molL^(-1)],[" methanoic acid is "46.1Scm^(2)mol^(-1)." Its degree "],[" of dissociation "(alpha)" and dissociation constant."],[" Given "lambda^(@)(H^(+))=349.6Scm^(2)mol^(-1)" and "],[lambda^(@)(HCOO^(-))=54.6Scm^(2)mol^(-1)" ."],[" (A) "K_(a)=3.67times10^(4)alpha=0.214],[" (B) "K_(a)^(a)=3.67times10^(-4)alpha=0.114],[" (C) "K_(a)^(a)=2.25times10^(-2)alpha=0.150],[" (D) "K_(a)=2.25times10^(-2)alpha=0.314]

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The molar conductivity of 0.025 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Its degree of dissociation (alpha) and dissociation constant. Given lambda^(@)(H^(+))=349.6 S cm^(-1) and lambda^(@)(HCOO^(-)) = 54.6 S cm^(2) mol^(-1) .

The molar conductivity of 0.025 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Its degree of dissociation (alpha) and dissociation constant. Given lambda^(@)(H^(+))=349.6 S cm^(-1) and lambda^(@)(HCOO^(-)) = 54.6 S cm^(2) mol^(-1) .

The molar conductivity of 0.025 mol L^(-1) methanoic acid is 46.1 S cm^(2) "mol^(-1) . Calculate its degree of dissociation and dissociation constant. Given, lambda^(@) ( H^(+)) = 349.6S cm^(2) "mol"^(-1) and lambda^(@) ( HCOO^(-)) = 54.6 S cm^(2) "mol"^(-1)

The molar conductivity of 0.024 "mol" L^(-1) methanoic acid is 46.1 S cm^(-2)"mol"^(-1) . Calculate its degree of dissociation and dissociation constant. Given lambda^(0)(H^(+) = 349.6 S cm^(2) mol^(-1) and lambda^(0)(HCOO^(-)) = 54.6 S cm^(2) mol^(-1) .

The molar conductivity of 0.025mol L^(-1) methanoic acid is 46.1 S cm^(2)mol ^(-1). Calculate its degree of dissociation and dissociation constant. Given, lamda^(0)(H^(+))=349.6S cm^(2) mol ^(-1) and lamda^(0)(HCOO^(-))=54.6S cm^(2)mol^(-1)