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[" (8) If "log(0.3)(x-1)<log(0.09)(x-1)"...

[" (8) If "log_(0.3)(x-1)

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The domain of the function f(x) = sqrt(-log_(0.3)(x-1))/sqrt(x^2 + 2x + 8) is

If log_(0.3) (x - 1) lt log_(0.09) (x - 1) , then x lies in the interval

If log_(0.3) (x-1) lt log_(0.09) (x-1) , then x lies in the interval :

If log_(0.3)(x-1)lt log_(0.09)(x-1) , then x lies in the interval

If log_(0.3) (x - 1) lt log_(0.09) (x - 1) , then x lies in the interval

If log_(0.3)(x-1) < log_(0.09)(x-1) , then x lies in the interval :

Find the value of x such that log_(0.3)(x-1) = log_(0.09)(x-1) .

If log_(0.3)(x-1)ltlog_(0.09)(x-1) ,then x lies in the interval

If log_(0.3)(x-1)ltlog_(0.09)(x-1) , then x lies in the interval