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[" Q.15Using the expression "2d" sin "th...

[" Q.15Using the expression "2d" sin "theta=lambda," one "],[" calculates the values of d by measuring the "],[" corresponding angles "theta" in the range "0" to "90^(@).],[" The wavelength "lambda" is exactly known and the "],[" error in "theta" is constant for all values of "theta." As "theta],[" increases from "0^(@),quad " IJEE-Advance "2013]],[" (1) the absolute error in d remains constant "],[" (2) the absolute error in d increases "],[" (3) the fractional error in d remains constant "],[" (4) the fractional error in d decreases "]

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