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Suppose an object has thickness du so that it extends from object distance u to u+du. Prove that the thickness dv of its image is given by (-v^2/u^2)du, so the longitudinal magnification (dv)/(du)=-m^2, where m is the lateral magnification.

Suppose an object has thickness du so that it extends from object distance u to u+du. Prove that the thickness dv of its image is given by (-v^2/u^2)du, so the longitudinal magnification (dv)/(du)=-m^2, where m is the lateral magnification.

If y=sinx and u=cosx, then (dy)/(du) is equal to

int_0^x{int_0^uf(t)dt}\ du is equal to (a) int_0^x(x-u)f(u)du (b) int_0^x uf(x-u)du (c) x int_0^xf(u)du (d) x int_0^x uf(u-x)du

int_0^x{int_0^uf(t)dx}\ du is equal to (a) int_0^x(x-u)f(u)du (b) int_0^x uf(x-u)du (c) x int_0^xf(u)du (d) x int_0^x uf(u-x)du

If u=ax+b, then (d^(n))/(dx^(n))(f(ax+b)) is equal to a.(d^(n))/(du^(n))(f(u)) b.a(d^(n))/(du^(n))(f(u)) c.a^(n)(d^(n))/(du^(n))f(u) d.a^(-n)(d^(n))/(dx^(n))(f(u))

The blue baby syndrome or cyanosis is caused du to pollution by cyanides.

If y = sin x^(@) " and " u = cos x " then " (dy)/(du) is equal to

If int_0^x {int_0^u f(t) dx}du is equal to (a) int_0^x (x-u) f(u) (b) int_0^xuf(x-u)du (c) x int_0^x f(u) du (d) x int_0^x uf(u-x)du

If int_0^x {int_0^u f(t) dt}du is equal to (a) int_0^x (x-u) f(u) (b) int_0^xuf(x-u)du (c) x int_0^x f(u) du (d) x int_0^x uf(u-x)du